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Q.

In the figure, a block of weight 60 N is placed on a rough surface. The coefficient of friction between the block and the surfaces is 0.5. What should be the weight W such that the block does not slip on the surface?

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a

60 N

b

602N

c

30 N

d

302N

answer is C.

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Detailed Solution

Frictional force:  f= μN = 0.5×mg = 0.5×60 = 30 NNow F = T1= T2cos 450or 30 = T2 cos 450and W = T2 sin 450Solving them we get W = 30 N
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