Questions
In the figure, a block of weight 60 N is placed on a rough surface. The coefficient of friction between the block and the surfaces is 0.5. What should be the weight W such that the block does not slip on the surface?
detailed solution
Correct option is C
Frictional force: f= μN = 0.5×mg = 0.5×60 = 30 NNow F = T1= T2cos 450or 30 = T2 cos 450and W = T2 sin 450Solving them we get W = 30 NTalk to our academic expert!
Similar Questions
A block of mass 5 kg is placed on a rough horizontal plane. A time dependent horizontal force F = (t2+2t)N acts on the block. The friction force between the block and the plane at t = 3 s is ()
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