In figure, the blocks are at rest and a force of 10 N acts on the block of 4kg mass. The coefficient of static friction and the coefficient of kinetic friction are μs=0.2 and μk=0.15 for both the surfaces in contact. The magnitude of friction force acting between the surface of contact between the 2 kg and 4 kg block in this situation is
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a
3N
b
4N
c
3.33 N
d
Zero
answer is D.
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Detailed Solution
The minimum value of F required to be applied on the blocks to move is =μsm1+m2g=0.2×(2+4)×10=12N. Since the applied force is less than the minimum value of force required to move the blocks together, the blocks will remain stationary.
In figure, the blocks are at rest and a force of 10 N acts on the block of 4kg mass. The coefficient of static friction and the coefficient of kinetic friction are μs=0.2 and μk=0.15 for both the surfaces in contact. The magnitude of friction force acting between the surface of contact between the 2 kg and 4 kg block in this situation is