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Q.

In figure, the blocks are at rest and a force of 10 N acts on the block of 4kg mass. The coefficient of static friction and the coefficient of kinetic friction are μs=0.2 and μk=0.15 for both the surfaces in contact. The magnitude of friction force acting between the surface of contact between the 2 kg and 4 kg block in this situation is

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a

3N

b

4N

c

3.33 N

d

Zero

answer is D.

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Detailed Solution

The minimum value of F required to be applied on the blocks to move is =μsm1+m2g=0.2×(2+4)×10=12N. Since the applied force is less than the minimum value of force required to move the blocks together, the blocks will remain stationary.
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