Q.

In figure, the charges on C1,C2  and  C3   are  Q1,Q2,Q3, respectively. Then

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a

Q2=8  μC

b

Q3=12  μC

c

Q1=20  μC

d

Q2=12  μC

answer is A.

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Detailed Solution

Effective capacitance is C=4×59=209μFCharge on C1  is Q1=CV=209×9=20  μCcharge on C2  is Q2(C2C2+C3)Q1=23×20=8  μCcharge on C3  is Q3=(C3C2+C3)Q1=33×20=12  μCSince, Q2C2=Q3C3and Q1=Q2+Q3=Q2+C3C2Q2=Q2(C2+C3C2)Therefore,Q2=(C2C2+C3)Q1Q3=(C3C2+C3)Q1Thus, options (1), (2), and (3) are correct
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