In Figure, coefficient of friction between the block and the floor is ‘µ’. Force F that will move the block on the floor with a uniform speed is

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(μsin⁡θ+cos⁡θ)mg

(μsin⁡θ−cos⁡θ)mg

μmgcos⁡θ−μsin⁡θ

μmgsin⁡θ−μcos⁡θ

answer is D.

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Detailed Solution

Normal reaction N=mg+Fcos⁡θFor constant speed Fnet =0⇒Fsin⁡θ−μN=0⇒Fsin⁡θ−μ(mg+Fcos⁡θ)=0⇒F=μmgsin⁡θ−μcos⁡θ

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