In the figure, the cross-sectional area of the smaller tube is a and that of the larger tube is 2a. A block of mass m is kept in the smaller tube having the same base area a, as that of the tube. The difference between water levels of the two tubes is
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a
P0ρg+maρ
b
P0ρg+m2aρ
c
maρ
d
m2ρa
answer is C.
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Detailed Solution
Pressure at the bottom level of the blockP=mga+P0The pressure at the same level remains the same.Hence mga+P0=hρg+P0⇒h=maρ