Questions
In the figure given below, the position - time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 sec is
a
0.2 kg m sec-1
b
-0.2 kg m sec-1
c
0.1 kg m sec-1
d
-0.4 kg m sec-1
detailed solution
Correct option is B
Velocity between t = 0 and t = 2 sec⇒ v1 = dxdt = 42 = 2 m/sVelocity at t = 2 sec, vf= 0Impulse = Change in momentum = m (vf-vf) 0.1(0-2) = -0.2 kg m sec-1Talk to our academic expert!
Similar Questions
Figures I, II, III and IV depict variation of force with time. Select the figure(s) that depicts minimum impulse delivered.
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