In the figure given below, the position - time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 sec is

Velocity between t = 0 and t = 2 sec⇒  v1 = dxdt = 42 = 2 m/sVelocity at t = 2 sec, vf= 0Impulse = Change in momentum = m (vf-vf)    0.1(0-2) = -0.2 kg m sec-1