Questions
In the figure given the position-time graph of a particle of mass 0.1 kg is shown. The impulse at t = 2 s is :
a
0.2 kg m s–1
b
0.3 kg m s–1 (2) – 0.2 kg m s–1
c
0.1 kg m s–1
d
– 0.4 kg m s–1
detailed solution
Correct option is A
If x=2t⇒v=axdt=2 Impulse = change of momentum = 0.1 × 2 – 0 = 0.2 kg m/sTalk to our academic expert!
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