Questions
In the figure given, the system is in equilibrium. What is the maximum value that W can have if the friction force on the 40 N block cannot exceed 12.0 N
detailed solution
Correct option is B
The free-body diagram of the block is as shown in adjacent figure. ∵f0max =12.0N( Given )∵T1max =12.0NThe free-body diagram of knot is as shown in adjacent figure. T2sin30∘=W … (i) T2cos 30∘=T1 … (ii) Divide (i) by (ii), we get, tan30∘=WT1 or W=T1tan30∘=0.577T1∴Wmax=0.577T1max=0.577×12.0N=6.92N.Talk to our academic expert!
Similar Questions
A block of mass 5 kg is placed on a rough horizontal plane. A time dependent horizontal force F = (t2+2t)N acts on the block. The friction force between the block and the plane at t = 3 s is ()
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
