First slide

Two block problem

Question

In the figure, m_A = 3kg and m_B = 4 kg. For what minimum value of F, A starts slipping over B:(g=10ms^–2)

Moderate

A

24N
B

41N
C

36N
D

20N

Solution

Minimum value of applied force for which A will slip over B is given by
${F_{\min }} = \left[ {{\mu _1}{m_A} + ({\mu _1} + {\mu _2}){m_B}} \right]g$
= (0.3 x 3 + 0.8 x 4) x 10N
= 41N

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