First slide

Constraints

Question

In Figure (A), mass m is lifted up by attaching a mass 2m to the other end of the string while in Figure (B), m is lifted by pulling the other end of the string with a constant force F = 2mg,then:

Easy

A

acceleration of m in the two situations is same and non-zero
B

acceleration of m in situation (A) is more than in situation (B)
C

acceleration of m in situation (A) is less than in situation (B)
D

acceleration of m in the two situations is same and equal to zero

Solution

For (A), acceleration = $= (\frac{2 m - m}{2 m + m}) g = \frac{g}{3}$
For (B), for motion of block,2mg - mg = ma = a = g

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App