In Figure (A), mass m is lifted up by attaching a mass 2m to the other end of the string while in Figure (B), m is lifted by pulling the other end of the string with a constant force F = 2mg,then:
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a
acceleration of m in the two situations is same and non-zero
b
acceleration of m in situation (A) is more than in situation (B)
c
acceleration of m in situation (A) is less than in situation (B)
d
acceleration of m in the two situations is same and equal to zero
answer is C.
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Detailed Solution
For (A), acceleration = =2m-m2m+mg=g3For (B), for motion of block,2mg - mg = ma = a = g
In Figure (A), mass m is lifted up by attaching a mass 2m to the other end of the string while in Figure (B), m is lifted by pulling the other end of the string with a constant force F = 2mg,then: