Questions
In Figure (A), mass m is lifted up by attaching a mass 2m to the other end of the string while in Figure (B), m is lifted by pulling the other end of the string with a constant force F = 2mg,then:
detailed solution
Correct option is C
For (A), acceleration = =2m-m2m+mg=g3For (B), for motion of block,2mg - mg = ma = a = gTalk to our academic expert!
Similar Questions
Two masses of I kg and 5 kg are attached to the ends of a massless string passing over a pulley of negligible weight. The pulley itself is attached to a light spring balance as shown in figure. The masses start moving during this interval; the reading of spring balance will be:
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