First slide

Capacitance

Question

In the figure a potential of +1200V is given to point A and point B is earthed, what is the potential at the point P?

Easy

A

100 V
B

200 V
C

400 V
D

600 V

Solution

Given circuit can be reduced as follows
In series combination charge on each capacitor remain same. So using Q = CV
$\Rightarrow C_{1} V_{1} = C_{2} V_{2} \Rightarrow 3 (1200 - V_{P}) = 6 (V_{P} - V_{B}) \Rightarrow 1200 - V_{P} = 2 V_{P} (∵ V_{B} = 0) \Rightarrow 3 V_{P} = 1200 \Rightarrow V_{P} = 400 volt$

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