Questions
In the figure a potential of +1200V is given to point A and point B is earthed, what is the potential at the point P?
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Correct option is C
Given circuit can be reduced as follows In series combination charge on each capacitor remain same. So using Q = CV⇒C1V1=C2V2⇒31200−VP=6VP−VB ⇒ 1200−VP=2VP ∵VB=0 ⇒ 3VP=1200⇒VP=400 voltSimilar Questions
Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
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