Questions
Figure represents a light inextensible string ABCDE in which AB = BC = CD = DE and to which are attached masses M, m, and M at the points B, C, and D, respectively.
The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. It is given that tan = 3/4 and tan = 12/5. Then the tension in the
string BC is
detailed solution
Correct option is B
tanβ=125 ∴cosβ=513T1cosβ+T2cosβ=mg ......(i)T1sinβ=T2sinβ ......(ii)∴ T1=T2=T∴ 2Tcosβ=mg ⇒T=mg2cosβ⇒T=1310mgTalk to our academic expert!
Similar Questions
Natural length of the spring is 40 cm and its spring constant is 4000 N m-1. A mass of 20 kg is hung from it. The extension produced in the spring is (Given g = 9.8 m s-2)
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