Download the app

Questions  

Figure represents a light inextensible string ABCDE in which AB = BC = CD = DE and to which are attached masses M, m, and M at the points B, C, and D, respectively. 

The system hangs freely in equilibrium with ends A and E of the string fixed in the same horizontal line. It is given that tan α = 3/4 and tan β = 12/5. Then the tension in the
string BC is

a
2 mg
b
(13/10) mg
c
(3/10) mg
d
(20/11) mg

detailed solution

Correct option is B

tan⁡β=125 ∴cos⁡β=513T1cos⁡β+T2cos⁡β=mg    ......(i)T1sin⁡β=T2sin⁡β    ......(ii)∴ T1=T2=T∴ 2Tcos⁡β=mg ⇒T=mg2cos⁡β⇒T=1310mg

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Natural length of the spring is 40 cm and its spring  constant is 4000 N m-1. A mass of 20 kg is hung  from it. The extension produced in the spring is (Given g = 9.8 m s-2


phone icon
whats app icon