Figure show the vertical section of a frictionless surface. A block of mass 2kg is  released from rest from position A; its KE as it reaches position C is (g=10ms-2)

Decrease in height is h = 14-7=7mTotal energy is conservedAlso KE at C = Loss in PE = mghsubstitute the given values m=2kg; g=10 m/square sec; h=7mKE at C =2(10)7KE at C= 140J