First slide

Conservation of mechanical energy

Question

Figure show the vertical section of a frictionless surface. A block of mass 2kg is released from rest from position A; its KE as it reaches position C is $(g = 10 m s^{- 2})$

Moderate

A

140J
B

180J
C

120J
D

280J

Solution

Decrease in height is h = 14-7=7m
Total energy is conserved
Also KE at C = Loss in PE = mgh
substitute the given values m=2kg; g=10 m/square sec; h=7m
KE at C =2(10)7
KE at C= 140J

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