In the figure shown, ABCDEF is a regular hexagon. What is the value of AB + AC + AD + AE + AF?
AO
2AO
4AO
6AO
AB+ AC+ AD+ AE+ AF
=AB+(AB+BC)+(AB+BC+CD)+(AB+BC+CD+DE)+AF
=4AB+3BC+2CD+DE+AF
(∵AB=-DE,BC=-EF,AF=CD)
=3(AB+BC+CD)=3AD=6AO