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Questions  

In the figure shown, ABCDEF is a regular hexagon. What is the value of AB + AC + AD + AE + AF?

a
AO
b
2AO
c
4AO
d
6AO

detailed solution

Correct option is D

AB+ AC+ AD+ AE+ AF=AB+(AB+BC)+(AB+BC+CD)+(AB+BC+CD+DE)+AF=4AB+3BC+2CD+DE+AF(∵AB=-DE,BC=-EF,AF=CD)=3(AB+BC+CD)=3AD=6AO

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