First slide

Connected bodies

Question

In the figure shown block B moves down with a velocity 10 m/s. The velocity of A in the position shown is

Difficult

A

12.5 m/s
B

25 m/s
C

6.25 m/s
D

None of these

Solution

If B moves down at 10m/s . Therefore length of the string between A and the pulley is decreasing at a rate of 20m/s
$V_{A} \cos 37 = 20 m / s V_{A} = \frac{20}{\cos 37} = 25 m / s$

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