In figure shown, both blocks are released from rest. The time to cross each other is
For A, 4g – T = 4a; For B, T–1g = a ⇒ a = 3g/5 aAB = 6g/5 = 12 m/s2
⇒ 6 = 1/2 x 12 x t2 ⇒ t = 1 sec