In the figure shown if mass of each block is m. Find the acceleration of block A. (use g=10 m/s2)
2 m/s2
4 m/s2
1 m/s2
5 m/s2
Let acc. of block A be aA and acc. of block B be aB. Hence
2T=maA--(1)andmg−4T=maB---(2)
Constrained Motion : 2TaA=4TaB∵T∝1a
⇒aA=2aB
After solving we get,
from 2×1 and 2⇒2 2T=maA⇒4T=2maA ⇒mg−4T=maA2on solving we get ⇒mg= 5maA2⇒aA=4ms−2