First slide
Application of Newtons laws
Question

In the figure shown if mass of each block is m. Find the acceleration of block A.  
(use g=10 m/s2)


 

Moderate
Solution

 

Let acc. of block A be aA  and acc. of block B be aB. Hence

2T=maA--(1)andmg4T=maB---(2)

Constrained Motion : 2TaA=4TaBT1a

aA=2aB

After solving we get, 

from 2×1 and 22 2T=maA4T=2maA                          mg4T=maA2on solving we get mg= 5maA2aA=4ms2

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