In the figure shown, initially spring is in unstretched state and blocks are at rest. Now 100 N force is applied on block A and B as shown in figure. After some time velocity of A becomes 2 m/s and that of B 4 m/s and block A displaced by amount 10 cm and spring is stretched by amount 30 cm. Then work done by spring force on A will be:
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
9/3 J
b
-6 J
c
6 J
d
none of these
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Wspring +W100N=Δk( on A)Wspring +(100)10100=12(2)(2)2Wspring =4−10=−6J