In the figure shown initially spring is in unstretched state and blocks are at rest. Now $$100$$ N force is applied on block A arrd B as shown in figure. After some time velocity of 'A' becomes $$2$$ $$m/s$$ and that of ' B' $$4$$ $$m/s$$ and block A displaced by amount $$10$$ cm and spring is stretched by amount $$30$$ crn. Then work done by spring force on A will be:

Question

Infinity Learn · Accepted Answer

Wspring $$+W100N=$$Δ$$k($$ on $$A)Wspring$$ $$+(100)10100=12(2)(2)2Wspring$$ $$=4$$−$$10=$$−$$6J$$

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