In the figure shown, the maximum and minimum currents through Zener diode are

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5 mA, 1 mA

14 mA, 6 mA

10 mA, 2 mA

9 mA, 1 mA

answer is C.

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Detailed Solution

As 10 kilo ohm is in parallel with Zener then voltage and current across it is constant and the current through the load is 4010×103=4 mAMinimum potential drop across 5 kilo ohm resistor is 70 - 40 = 30 V and current is 305×103=6 mAcurrent through Zener is 6 - 4 = 2 mAmaximum voltage drop across the 5 Kilo ohm resistor is 110 - 40 = 70 Vmaximum current 705×103=14 mA maximum current through Zener 14-4=10 mA

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