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Q.

In the figure shown, a particle of mass m is released from the position A on a smooth track. When the particle reaches at B, then normal reaction on it by the track is

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a

mg

b

2mg

c

23mg

d

m2 g h

answer is A.

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Detailed Solution

By conservation of energy mg(3 h)=mg(2 h)+12mv2(here v=velocity at B)⇒mgh=12mv2⇒v=2gh From free body diagram of block at B  N+mg=mv2 h=2mg⇒N=mg
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