Q.

In the figure shown, the potential drop across each capacitor is (assume diodes to be ideal)

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a

12V, 12V

b

16V, 8V

c

Zero, 24V

d

8V, Zero

answer is B.

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Detailed Solution

The diode connected parallel to the battery is reverse bias. So, current will not pass through it. So, total emf divided among C1  and   C2and in the inverse ratio of their capacitances.V=2CV1V2=C2C1V1=VC2C1+C2,  V2=VC1C1+C2
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