Questions
In the figure shown, the potential drop across each capacitor is (assume diodes to be ideal)
detailed solution
Correct option is B
The diode connected parallel to the battery is reverse bias. So, current will not pass through it. So, total emf divided among C1 and C2and in the inverse ratio of their capacitances.V=2CV1V2=C2C1V1=VC2C1+C2, V2=VC1C1+C2Talk to our academic expert!
Similar Questions
Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
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