Q.
Figure shows a capacitor made of two circular plates, each of radius 12 cm and separated by 5.0 mm. The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A. Calculate the rate of change of potential difference between the plates (in 109 V/s).
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answer is 1.87.
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Detailed Solution
Area of one of the plates, A=π12×10−22 m2Distance between the plates, d=5.0mm=5×10−3 mCapacitance of the capacitor, C=ϵ0Ador C=14π×9×109×π12×10−225×10−3 =80×10−12 F=80 pFCharging current, I=dQdt=ddt(CV) or I=CdVdt or dVdt=ICRate of change of p.d.=dVdt=IC=0.15 A80×10−12 F=1.87×109 V/s
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