Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated on the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is [NCERT Exemplar]

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

x(t)=B sin2πt30

b

x(t)=B cosπt15

c

x(t)=B sinπt15+π2

d

x(t)=B cosπt15+π2

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let angular velocity of the particle executing circular motion is ω and when it is at Q, it makes an angle θ as shownin the diagram.Clearly, θ =ωtNow, we can write OR              =OQ cos (90°-θ)              =OQ sin θ = OQ sin ωt               =r sin ωt                                                         (∵ OQ = r)⇒        x = r sin ωt = B sin ωt                                          (∵ r=B)                =B sin2πTt=B sin2π30tClearly, this equation represents SHM.
Watch 3-min video & get full concept clarity
score_test_img

courses

No courses found

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon
Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated on the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is [NCERT Exemplar]