Q.
Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated on the figure. The simple harmonic motion of the x-projection of the radius vector of the rotating particle P is [NCERT Exemplar]
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a
x(t)=B sin2πt30
b
x(t)=B cosπt15
c
x(t)=B sinπt15+π2
d
x(t)=B cosπt15+π2
answer is A.
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Detailed Solution
Let angular velocity of the particle executing circular motion is ω and when it is at Q, it makes an angle θ as shownin the diagram.Clearly, θ =ωtNow, we can write OR =OQ cos (90°-θ) =OQ sin θ = OQ sin ωt =r sin ωt (∵ OQ = r)⇒ x = r sin ωt = B sin ωt (∵ r=B) =B sin2πTt=B sin2π30tClearly, this equation represents SHM.