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# Figure shows a conducting circular loop of radius a placed in a uniform, perpendicular magnetic field B. A thick metal rod OA is pivoted at the centre O. The other end of the rod touches the loop at A. The centre O and a fixed point C on the loop are  connected by a wire OC of resistance R. A force is applied at the middle point of the rod OA perpendicularly, so that the rod rotates clockwise at a uniform angular velocity $\omega$. Find the force

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a
ωa3B2R to the right of OA in the figure
b
ωa3B22R to the right of OA in the figure
c
ωa3B2R to the left of OA in the figure
d
None of these

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detailed solution

Correct option is B

e=Bvl=B×a×ω×a2i=Ba2ω2RF=ilB=Ba2ω2R×a×B=B2a3ω2Rtowards right of OA

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