Figure shows a conducting frame having battery and a resistance on which a movable conductor of length $$0.5$$ m can slide. The whole arrangement is placed in a uniform magnetic field of B $$=$$ $$0.4$$ T directed perpendicular and into the plane of frame. Initially the circuit is open. When the key is inserted, the conductor begins to move. It is found that a force $$0.5$$ N has to be applied on the conductor to the left to keep it moving at constant speed to the right. Current flowing in the conductor is:

Question

Infinity Learn · Accepted Answer

$$F=Bil$$⇒$$i=FBl=0.50.4$$×$$0.5=2.5A$$

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