Questions
Figure shows a conducting loop ABCDA placed in a uniform magnetic field (strength B) perpendicular to its plane. The part ABC is the (three-fourth) portion of the square of side length l. The part ADC is a circular arc of radius R. The points A and C are connected to a, battery which supplies a current i to the circuit.The magnetic force on the loop due to the field B is
detailed solution
Correct option is B
F=Bi1l+Bi2l⇒ F=Bli1+i2=BilTalk to our academic expert!
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A uniform field exists in region of space. A semicircular wire of radius 1 m carrying current 1A having its centre at (2, 2, 0) is placed in x-y plane as shown in figure. The force on semi circular wire will be
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