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Q.

The figure shows  a  crude  type  of  perfume  atomizer.  When  bulb  at  A  is  compressed,  air  flows swiftly  through  the  tube  BC  with  uniform  speed  v,  there  by  causing  a  reduced  pressure  at  the top position of vertical tube DE. The liquid of density 500 kg/m3, then rises in the tube, enters tube BC and sprayed out. When bulb is in natural position the air in the bulb and tube are at atmospheric pressure P0=105N/m2. When bulb A is compressed, it creates an excess pressure Δp=0.001  P0  inside the bulb A.  Density of air is 1.3  kg/m3.  If the magnitude of  minimum  value  of  speed  v, required to cause the liquid to rise to tube BC is 5k m/s. Find the value of k. (g = 10 m/s2 ).

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answer is 4.

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Detailed Solution

Use Bernoulli’s equation at point-3 and point-4, we can write P0+ΔPρair=PBCρair+12v2⇒PBC=P0+ΔP−0.65  v2Using Bernoulli’s equation at point-1 and point-2, we can writeP1ρliquid+12vliquid2=P2ρliquid​⇒    PBC+ρliquidghρliquid+12vℓ2=P0ρℓ​⇒    P0+ΔP+ρℓgh−0.65v2ρℓ+12vℓ2=P0ρℓ​⇒  12ρℓvℓ2=0.65 v2−ΔP−ρℓgh≥0​⇒   v2≥ΔP+ρℓgh0.65​⇒vmin=ΔP+ρℓgh0.65=1005=20  m/s
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