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Q.

Figure shows a cubical block of side 10 cm and relative density 1.5 suspended by a wire of cross-sectional area 10-6m2.The breaking stress of the wire is 7 x 106 N/m2. The block is placed in a beaker of base area 200 cm2 and initially i.e. at t=0, the top surface of water and the block coincide. There is a pump at the bottom corner which ejects 2 cm3 of water per sec. If the time at which the wire will break is N x 102 sec. The value of N is_______.

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Detailed Solution

Breaking force = Breaking stress × area of wire =7×106×10−6=7N weight of block =vol× density ×g=10−3×1.5×103×10=15N The up thrust when the liquid level has descended by ×cm . =100(10−x)⋅10−6⋅103.10=10−x Newton. ∴ Net downward force on the block =15−(10−x)=5+x= Tension T∴ The wire will break when 5+x=7 .  i.e. when x=2cmLet the level descends by 2 cm in t time thent = 100 sec.
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