Figure shows a cyclic process ABCDBEA. performed on an ideal cycle. lf If PA = 2 atm, PB = 5 atm and Pc = 6 atm. VE-VA= 20 litre, find the work done by the gas in the complete, process (l atm. pressure = 1×105 Pa)

The complete cyclic process can be visualized as made up of two cycles, i.e., cycle AEBA (clockwise) and cycle BDCB (counter-clockwise).Work done by the gas during the cycle AEBA should be positive,W1 = area of the loop in the P-V diagram      = 12(base)(altitude) = 12(VE-VA)(PB-PA)       = 12(20×10-3m3)(5-2)×105 Nm-2 = 3kJWork done by the gas the cycle BDCB should be negative,W2 = -(area of loop BDCB)Now evidently, triangles ABE and BCD are similar, the corresponding angles being equal (i.e.,