Q.

Figure shows a cyclic process performed on one mole of an ideal gas. A total of 1000 J of heat is withdrawn from the gas in a complete cycle. Find the work done on/by the gas, in joule, during the process B→C. Given R = 8.3 J mol-1 K-1

Moderate

Unlock the Full Solution and Master the Concept

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya

answer is 1830.

(Detailed Solution Below)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

For a cyclic process, ΔU=0⇒ Qcycle =Wcycle    ……..(1)where, Wcycle =WA→B+WB→C+WC→A …….(2)Process C→A is isochoric, hence WC→A=0Process A →B is isobaric, as its T-V graph is a straight line passing through origin.In an isobaric process, work done is         WA→B=PVB−VA=nRTB−TA⇒ WA→B=1×8.3(400−300)=830J    ........(3)WA→B is positive, so expansion of gas takes place.From equations (1), (2) and (3), we get−1000=830+WB→C+0⇒ WB→C=−1830 JNegative work done implies that compression of the gas takes place or work is done on the system/gas.
ctaimg
Choose your Grade and Exam
edit icon

Connect with our

Expert Counsellors

access to India's best teachers with a record of producing top rankers year on year.

+91

We will send a verification code via OTP.

whats app icon