Download the app

Thermodynamic processes

Question

Figure shows a cyclic process performed on one mole of an ideal gas. A total of 1000 J of heat is withdrawn from the gas in a complete cycle. Find the work done on/by the gas, in joule, during the process BC. Given R = 8.3 J mol-1 K-1 

Moderate
Solution

For a cyclic process, ΔU=0

 Qcycle =Wcycle    ……..(1)

where, Wcycle =WAB+WBC+WCA …….(2)

Process CA is isochoric, hence WCA=0

Process A B is isobaric, as its T-V graph is a straight line passing through origin.

In an isobaric process, work done is

         WAB=PVBVA=nRTBTA WAB=1×8.3(400300)=830J    ........(3)

WAB is positive, so expansion of gas takes place.

From equations (1), (2) and (3), we get

1000=830+WBC+0 WBC=1830 J

Negative work done implies that compression of the gas takes place or work is done on the system/gas.



Talk to our academic expert!

+91

Are you a Sri Chaitanya student?



Similar Questions

 In the given graph, an ideal gas can change its state from A to C by two paths ABC or AC. Taking, the internal energy of gas at ‘A’ is 10 J, mark the CORRECT option(s)


phone icon
whats app icon