First slide
Thermodynamic processes
Question

Figure shows a cyclic process performed on one mole of an ideal gas. A total of 1000 J of heat is withdrawn from the gas in a complete cycle. Find the work done on/by the gas, in joule, during the process BC. Given R = 8.3 J mol-1 K-1 

Moderate
Solution

For a cyclic process, ΔU=0

 Qcycle =Wcycle    ……..(1)

where, Wcycle =WAB+WBC+WCA …….(2)

Process CA is isochoric, hence WCA=0

Process A B is isobaric, as its T-V graph is a straight line passing through origin.

In an isobaric process, work done is

         WAB=PVBVA=nRTBTA WAB=1×8.3(400300)=830J    ........(3)

WAB is positive, so expansion of gas takes place.

From equations (1), (2) and (3), we get

1000=830+WBC+0 WBC=1830 J

Negative work done implies that compression of the gas takes place or work is done on the system/gas.

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