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Q.

Figure shows the displacement –time graphs of two simple harmonic motions I and II from the graph it follows that

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a

Curve I has same frequency as that of curve –II

b

Curve I has frequency twice that of curve-II

c

Curve I has frequency half that of curve-II

d

Curve I has frequency four times that of curve-II

answer is B.

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Detailed Solution

For curve - I, cycle timeT1 = (5-1)sec = 4secFor curve- II, cycle timeT2 = (10-2)sec = 8 secand
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