Figure shows the displacement –time graphs of two simple harmonic motions I and II from the graph it follows that

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Curve I has same frequency as that of curve –II

Curve I has frequency twice that of curve-II

Curve I has frequency half that of curve-II

Curve I has frequency four times that of curve-II

answer is B.

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Detailed Solution

For curve - I, cycle timeT1 = (5-1)sec = 4secFor curve- II, cycle timeT2 = (10-2)sec = 8 secand

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