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Figure shows the displacement –time graphs of two simple harmonic motions I and II from the graph it follows that

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a
Curve I has same frequency as that of curve –II
b
Curve I has frequency twice that of curve-II
c
Curve I has frequency half that of curve-II
d
Curve I has frequency four times that of curve-II

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detailed solution

Correct option is B

For curve - I, cycle timeT1 = (5-1)sec = 4secFor curve- II, cycle timeT2 = (10-2)sec = 8 secand


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