First slide

Second law

Question

The figure shows the force versus time graph for a particle. Then

Moderate

A

change in momentum of the particle is 40N-s
B

average force acting on the particle is 30N
C

change in momentum of the particle is 20N-s
D

average force acting on the particle is 25N

Solution

change in momentum = Area under F-t graph = $\frac{1}{2} x 0.4 x 100 N - s = 20 N - s$
Average force = $\frac{change in momentum}{Time interval} = \frac{20}{0.4} N = 50 N$

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