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Q.

The figure shows four wire loops, with edge lengths of either L or 2L. All four loops will move through a region of uniform magnetic field B→ (directed out of the page) atthe same constant velocity. Rank the four loops according to the maximum magnitude of the e.m.f. induced as they move through the field, greatest first

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a

εc=εd<εa=εb

b

εc=εd>εa=εb

c

εc>εd>εb>εa

d

εc<εd<εb<εa

answer is B.

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Detailed Solution

Emf induced across the length of the wire which cuts the magnetic field depends on length of that side of wire. (Length of c = Length d) > (Length of a =length of  b). So (εc=εd)>(εa=εb) Induced emf =e =B v L  where B=magnetic field , v=velocity of the conductor ,and lL=length of the coductor
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