The figure shows four wire loops, with edge lengths of either L or 2L. All four loops will move through a region of uniform magnetic field B→ (directed out of the page) atthe same constant velocity. Rank the four loops according to the maximum magnitude of the e.m.f. induced as they move through the field, greatest first
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a
εc=εd<εa=εb
b
εc=εd>εa=εb
c
εc>εd>εb>εa
d
εc<εd<εb<εa
answer is B.
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Detailed Solution
Emf induced across the length of the wire which cuts the magnetic field depends on length of that side of wire. (Length of c = Length d) > (Length of a =length of b). So (εc=εd)>(εa=εb) Induced emf =e =B v L where B=magnetic field , v=velocity of the conductor ,and lL=length of the coductor