Q.
The figure (6) shows fraunhoffer's diffraction due to a single slit. It first minimum is obtained in the direction shown, then the path difference between rays 1 and 3 is
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a
0
b
λ/4
c
λ/2
d
λ
answer is D.
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Detailed Solution
The condition for minimum intensity in case of single slit is given byesinθ=±mλThis equation gives the directions of first, second, third,... minima by putting m = 1,2,3,...,etc. For first minima(m= 1)dsinθ=λ Path difference between rays 1 and 3rd is λ.
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