Figure shows a $$5$$ kg ladder hanging from a string that is connected with a ceiling and is having a spring balance connected in between. A boy of mass $$25$$ kg is climbing up the ladder at acceleration $$1$$ $$m/s2$$. Assuming the spring balance and the string to be massless and the spring to show a constant reading, the reading of the spring balance is (Take$$ g $$=$$ $$10$$ $$m/s2)

Question

Infinity Learn · Accepted Answer

If reading of spring balance is T, then applying NLM on (man$$ $$+$$ $$ladder) system T−(25+5)g=25aT$$−$$30g=25a$$⇒T−$$300=25(1)⇒$$T=325N=32.5kg$$

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