The figure shows a metallic plate of uniform thickness and density. The value of l in terms of L so that the centre of mass of the system lies at the interface of the triangular and rectangular portion is
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a
l=L2
b
l=L3
c
l=L3
d
l=2L3
answer is C.
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Detailed Solution
If the interface is taken as the origin then l2bl-L312bL=0Center of mass of the triangle is L3from the base.m1x1+m2x2m1+m2=0Here mass is proportional to area I2=L23