First slide

meter bridge

Question

The figure shows a meter-bridge circuit where $X = 12 Ω$ and $R = 18 Ω$ . The jockey J is at the null point. If R is made $8 Ω$ through what distance will the jockey J have to be moved to obtain null point again?

Moderate

A

10 cm
B

20 cm
C

30 cm
D

40 cm

Solution

$\frac{AJ}{100 - AJ} = \frac{X}{R} = \frac{12}{18} \Rightarrow AJ = 40 cm$
After changing R:
$\begin{array}{l} \frac{{AJ}^{'}}{100 - {AJ}^{'}} = \frac{12}{8} \Rightarrow {AJ}^{'} = 60 cm \\ Shifting : {AJ}^{'} = 20 cm \end{array}$

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