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Resistors

Question

Figure shows a network of resistances connected to a 2V battery. If the internal resistance of the battery is negligible, current I in the circuit is

Moderate
Solution

Because P/Q = R/S, the circuit is a balanced Wheatstone's bridge. Therefore, potential at B = potential at D. Hence no current flows through the 5Ω resistor; it is, therefore, not effective. The equivalent resistance between A and C is the resistance of a parallel combination of P+R = 2+4 6Ω and Q+ S= 4+8 12Ω, which is given by

1R=16+112R=4Ω. Therefore current I is I=2V4Ω=0.5A



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Three resistances of 2Ω each are connected to a 2V battery as shown in Fig. Then


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