Questions
Figure shows a plank of mass m moving at speed u on a smooth surface. A spinning ball (sphere) of mass m and radius r normally strikes it at speed v. The friction coefficient between ball and upper surface of plank is = 0.5 and coefficient of restitution is e = 0.5. Find the angular velocity of sphere just after collision.
detailed solution
Correct option is B
As shown in figure if we write impulse = change in momentumequations mu−J2=mv2 mv−J1=−mv2 ⇒J1=32mv 0+J2=mv1⇒v1=32μv=34vvelocity of ball vball=(v/2)2+(3v/4)2=134vwe also have 25mr2ω−J2r=25mr2ω125mr2ω−μ32mvr==25mr2ω1ω1=154μvrTalk to our academic expert!
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A boy stands over the centre of a horizontal platform which is rotating freely with a speed of 2 revolutions/s about a vertical axis through the centre of the platform and straight up through the boy. He holds 2 kg masses in each of his hands close to his body. The. combined moment of inertia of the system is 1 kgmetre2. The boy now stretches his arms so as to hold the masses far from his body. In this situation, the moment of inertia of the system increases to 2kgmetre2. The kinetic energy of the system in the latter case as compared with that in the previous case will
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