First slide

Photoelectric effect and study of photoelectric effect

Question

Figure shows the plot of the stopping potential versus the frequency of the light used in an experiment on photoelectric effect. The ratio h/e is

Moderate

A

$10^{- 15} Vs$
B

$2 \times 10^{- 15} Vs$
C

$3 \times 10^{- 15} Vs$
D

$4.14 \times 10^{- 15} Vs$

Solution

$\begin{array}{l} e V_{s} = h v - ϕ_{0} \\ V_{s} = \frac{h}{e} v - \frac{ϕ_{0}}{e} \\ Now, \frac{h}{e} = slope = \frac{1.656}{4 \times 10^{14}} = 0.414 \times 10^{- 14} Vs \\ = 4.14 \times 10^{- 15} Vs \end{array}$

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