Figure shows the plot of the stopping potential versus the frequency of the light used in an experiment on photoelectric effect. The ratio h/e is

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10−15Vs

2×10−15Vs

3×10−15Vs

4.14×10−15Vs

answer is D.

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Detailed Solution

eVs=hv−ϕ0Vs=hev−ϕ0e Now, he= slope =1.6564×1014=0.414×10−14Vs =4.14×10−15Vs

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