Figure shows a square loop of side $$0.5$$ m and resistance $$10$$ Ω. The magnetic field has a magnitude B $$=$$ $$1.0$$ T. The work done in pulling the loop out of the field slowly and uniformly in $$2.0$$ s is

Question

Figure shows a square loop of side $$0.5$$ m and resistance $$10$$ Ω. The magnetic field has a magnitude B $$=$$ $$1.0$$ T. The work done in pulling the loop out of the field slowly and uniformly in $$2.0$$ s is

Infinity Learn · Accepted Answer

Speed of the loop should $$bev=$$ℓ$$t=0.52=0.25m/sInduced$$ emf, $$e=Bv$$ℓ$$=(1.0)(1.0)(0.25)(0.5)=$$ $$0.125$$ V∴      Current in the loop, $$i=eR=0.12510=1.25$$×$$10$$−$$2$$ AThe magnetic force on the left arm due to the magnetic field $$isFm=i$$ℓ $$B=1.25$$×$$10$$−$$2(0.5)(1.0)=6.25$$×$$10$$−$$3$$ NTo pull the loop uniformly, an external force of $$6.25$$×$$10$$−$$3$$ N towards right must be applied.∴$$W=6.25$$×$$10$$−$$3$$ $$N(0.5m)=3.125$$×$$10$$−$$3$$ J

Figure shows a square loop of side 0.5 m and resistance $10 Ω .$ The magnetic field has a magnitude B = 1.0 T. The work done in pulling the loop out of the field slowly and uniformly in 2.0 s is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Figure shows a square loop of side 0.5 m and resistance 10 Ω. The magnetic field has a magnitude B = 1.0 T. The work done in pulling the loop out of the field slowly and uniformly in 2.0 s is

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

Figure shows a square loop of side 0.5 m and resistance $10 Ω .$ The magnetic field has a magnitude B = 1.0 T. The work done in pulling the loop out of the field slowly and uniformly in 2.0 s is