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Figure shows a square loop of side 1m and resistance $1 Ω$ the magnetic field on left side of line PQ has a magnitude B = 1T. The work done in pulling the loop out of the field uniformly in 1s is

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Correct option is A

Given side of square loop l=1 mTime t=1 s Magnetic field B=1 TElectro motive force induced in loop due to its velocityε=Blv Current i=εR=BlvR∴i=1×1×11=1A Work done in pulling the loop isW=MB1−B2⇒W=niAB1−B2⇒W=1×1×12[1]∴W=1J

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