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Questions  

The figure shows three circuits with identical batteries, inductors, and resistors. Rank the circuits according to the current through the battery (i) just after the switch is closed and (ii) a long time later, greatest first.

[i1, i2 and i3 are respective current in circuit (1), (2) and, (3)]

 

a
(i) i2>i3>i1i1=0  (ii) i2>i3>i1
b
(i) i2i1i1≠0  (ii) i2>i3>i1
c
(i) i2=i3=i1i1=0  (ii) i2>i3>i1
d
(i) i2=i3>i1i1≠0  (ii) i2>i3>i1

detailed solution

Correct option is A

Just after the switch is closed maximum emf is induced in the inductor which opposes the flow of current and the current in the inductor becomes zero . So i1=0, i2=ER and i3=E2R. Hence i2>i3>i1. A long time after the key is closed, the inductor behaves like a resistanceless wire Therefore ,i1=E2R,i2=ER2=2ERand i3=ER. So i2>i3>i1.

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In the circuit shown, one of the inductors used is ideal. The potential difference across the batteries is10 V. The current drawn from the battery at steady state, after the switch is closed is


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