Figure shows three spherical and equipotential surfaces 1,2 and 3 round a point charge q. The potential difference V1–V2 = V2 – V3. If t1 and t2 be the distance between them. Then
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a
t1=t2
b
t1>t2
c
t1
d
t1≤t2
answer is C.
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Detailed Solution
V1−V2=kq1r1−1r2r2−r1=V1−V2r1r2kq; but r2−r1=t∴t α r1r2 if P.D is constant then r2−r1=t