First slide

laws

Question

Figure shows two flasks connected to each other. The volume of the flask 1 is twice that of flask 2. The system is filled with an ideal gas at temperatures 100 K and 200 K, respectively. If the mass of the gas in flask 1 is m, then what is the mass of the gas in flask 2?

Moderate

A

m
B

m/2
C

m/4
D

m/8

Solution

$p V = \frac{m}{M} R T \Rightarrow V \propto m T \Rightarrow \frac{V_{1}}{V_{2}} = \frac{m_{1}}{m_{2}} \cdot \frac{T_{1}}{T_{2}}$
$\Rightarrow$ $\frac{2 V}{V} = \frac{m}{m_{2}} \times \frac{100}{200} \Rightarrow m_{2} = \frac{m}{4}$

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