Questions
Figure shows two identical parallel plate capacitors connected to a battery through a switch S. Initially, the switch is closed so that the capacitors are completely charged. The switch is now opened and the free space between the plates of the capacitors is filled with a dielectric of dielectric constant 3. Find the ratio of the initial total energy stored in the capacitors to the final total energy stored
detailed solution
Correct option is D
Initial total energy =12CV2+12CV2=CV2When the switch is open, dielectric is introduced. Then capacitance, C = KC = 3C. Energy stored in C is =123CV2=32CV2Since the switch is open, charge will be the same in B so energy is B=12C3V2So total final energy =32CV2+16CV2=9CV2+1CV26=106CV2So required ratio =CV2106CV2=35=3:5Similar Questions
Figure shows a capacitor made of two circular plates, each of radius 12 cm and separated by 5.0 mm. The capacitor is being charged by an external source (not shown in figure). The charging current is constant and equal to 0.15 A. Calculate the rate of change of potential difference between the plates (in 109 V/s).
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