First slide
Photo Electric Effect
Question

 The figure (1) shows the variation of photo current with anode potential for a photo-sensitive surface for three different radiations. Let Ia,Ib and Ic be the  intensities and fa,fb and fc  be the frequencies for the curves a.b and c respectively
 

Moderate
Solution

 It is obvious from the figure (1) that tho stopping potential for curve (a) and (b) is the same. Therefore fa=fb This is because, the stopping potential V0 is frequency dependent hW0=eV0. Here W is the work function of the metal. We also know that saturation current is proportional to intensity of the incident radiation. So Ia<Ib i.e., IaIb

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