Figure shows the vertical section of a frictionless surface. A block of mass 2 kg is released from rest from position A; its KE as it reaches position C is (g = 10 ms-2)
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a
140 J
b
180 J
c
120 J
d
280 J
answer is A.
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Detailed Solution
Decrease in height: h =14 - 7 = 7m Also KE at C = Loss in PE = mgh = 140J
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Figure shows the vertical section of a frictionless surface. A block of mass 2 kg is released from rest from position A; its KE as it reaches position C is (g = 10 ms-2)