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In the figure, the velocities are in ground frame and the cylinder is performing pure rolling on the plank, velocity of point 'A' would be
detailed solution
Correct option is C
For pure rolling velocity of the point of contact has to be equal to the velocity of the surface.Let us say cylinder rolls with angular velocity ω.At point B,vC−ωr=vP⇒ωr=vC−vPAt point A,vA=vC+ωr=2vC−vPTalk to our academic expert!
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A homogeneous solid cylindrical roller of radius R and mass M is pulled on a cricket pitch by a horizontal force. Assuming rolling without slipping, angular acceleration of the cylinder is
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